I have a Unicode string in Python, and I would like to remove all the accents (diacritics).

I found on the web an elegant way to do this (in Java):

  1. convert the Unicode string to its long normalized form (with a separate character for letters and diacritics)
  2. remove all the characters whose Unicode type is “diacritic”.

Do I need to install a library such as pyICU or is this possible with just the Python standard library? And what about python 3?

Important note: I would like to avoid code with an explicit mapping from accented characters to their non-accented counterpart.

Unidecode is the correct answer for this. It transliterates any unicode string into the closest possible representation in ascii text.


accented_string = u'Málaga'
# accented_string is of type 'unicode'
import unidecode
unaccented_string = unidecode.unidecode(accented_string)
# unaccented_string contains 'Malaga'and is of type 'str'

How about this:

import unicodedata
def strip_accents(s):
   return ''.join(c for c in unicodedata.normalize('NFD', s)
                  if unicodedata.category(c) != 'Mn')

This works on greek letters, too:

>>> strip_accents(u"A \u00c0 \u0394 \u038E")
u'A A \u0394 \u03a5'

The character category “Mn” stands for Nonspacing_Mark, which is similar to unicodedata.combining in MiniQuark’s answer (I didn’t think of unicodedata.combining, but it is probably the better solution, because it’s more explicit).

And keep in mind, these manipulations may significantly alter the meaning of the text. Accents, Umlauts etc. are not “decoration”.

I just found this answer on the Web:

import unicodedata

def remove_accents(input_str):
    nfkd_form = unicodedata.normalize('NFKD', input_str)
    only_ascii = nfkd_form.encode('ASCII', 'ignore')
    return only_ascii

It works fine (for French, for example), but I think the second step (removing the accents) could be handled better than dropping the non-ASCII characters, because this will fail for some languages (Greek, for example). The best solution would probably be to explicitly remove the unicode characters that are tagged as being diacritics.

Edit: this does the trick:

import unicodedata

def remove_accents(input_str):
    nfkd_form = unicodedata.normalize('NFKD', input_str)
    return u"".join([c for c in nfkd_form if not unicodedata.combining(c)])

unicodedata.combining(c) will return true if the character c can be combined with the preceding character, that is mainly if it’s a diacritic.

Edit 2: remove_accents expects a unicode string, not a byte string. If you have a byte string, then you must decode it into a unicode string like this:

encoding = "utf-8" # or iso-8859-15, or cp1252, or whatever encoding you use
byte_string = b"café"  # or simply "café" before python 3.
unicode_string = byte_string.decode(encoding)

Actually I work on project compatible python 2.6, 2.7 and 3.4 and I have to create IDs from free user entries.

Thanks to you, I have created this function that works wonders.

import re
import unicodedata

def strip_accents(text):
    Strip accents from input String.

    :param text: The input string.
    :type text: String.

    :returns: The processed String.
    :rtype: String.
        text = unicode(text, 'utf-8')
    except (TypeError, NameError): # unicode is a default on python 3 
    text = unicodedata.normalize('NFD', text)
    text = text.encode('ascii', 'ignore')
    text = text.decode("utf-8")
    return str(text)

def text_to_id(text):
    Convert input text to id.

    :param text: The input string.
    :type text: String.

    :returns: The processed String.
    :rtype: String.
    text = strip_accents(text.lower())
    text = re.sub('[ ]+', '_', text)
    text = re.sub('[^0-9a-zA-Z_-]', '', text)
    return text


text_to_id("Montréal, über, 12.89, Mère, Françoise, noël, 889")
>>> 'montreal_uber_1289_mere_francoise_noel_889'

This handles not only accents, but also “strokes” (as in ø etc.):

import unicodedata as ud

def rmdiacritics(char):
    Return the base character of char, by "removing" any
    diacritics like accents or curls and strokes and the like.
    desc = ud.name(char)
    cutoff = desc.find(' WITH ')
    if cutoff != -1:
        desc = desc[:cutoff]
            char = ud.lookup(desc)
        except KeyError:
            pass  # removing "WITH ..." produced an invalid name
    return char

This is the most elegant way I can think of (and it has been mentioned by alexis in a comment on this page), although I don’t think it is very elegant indeed.
In fact, it’s more of a hack, as pointed out in comments, since Unicode names are – really just names, they give no guarantee to be consistent or anything.

There are still special letters that are not handled by this, such as turned and inverted letters, since their unicode name does not contain ‘WITH’. It depends on what you want to do anyway. I sometimes needed accent stripping for achieving dictionary sort order.


Incorporated suggestions from the comments (handling lookup errors, Python-3 code).

In response to @MiniQuark’s answer:

I was trying to read in a csv file that was half-French (containing accents) and also some strings which would eventually become integers and floats.
As a test, I created a test.txt file that looked like this:

Montréal, über, 12.89, Mère, Françoise, noël, 889

I had to include lines 2 and 3 to get it to work (which I found in a python ticket), as well as incorporate @Jabba’s comment:

import sys 
import csv
import unicodedata

def remove_accents(input_str):
    nkfd_form = unicodedata.normalize('NFKD', unicode(input_str))
    return u"".join([c for c in nkfd_form if not unicodedata.combining(c)])

with open('test.txt') as f:
    read = csv.reader(f)
    for row in read:
        for element in row:
            print remove_accents(element)

The result:


(Note: I am on Mac OS X 10.8.4 and using Python 2.7.3)

gensim.utils.deaccent(text) from Gensim – topic modelling for humans:

'Sef chomutovskych komunistu dostal postou bily prasek'

Another solution is unidecode.

Note that the suggested solution with unicodedata typically removes accents only in some character (e.g. it turns '?' into '', rather than into 'l').

In my view, the proposed solutions should NOT be accepted answers. The original question is asking for the removal of accents, so the correct answer should only do that, not that plus other, unspecified, changes.

Simply observe the result of this code which is the accepted answer. where I have changed “Málaga” by “Málagueña:

accented_string = u'Málagueña'
# accented_string is of type 'unicode'
import unidecode
unaccented_string = unidecode.unidecode(accented_string)
# unaccented_string contains 'Malaguena'and is of type 'str'

There is an additional change (ñ -> n), which is not requested in the OQ.

A simple function that does the requested task, in lower form:

def f_remove_accents(old):
    Removes common accent characters, lower form.
    Uses: regex.
    new = old.lower()
    new = re.sub(r'[àáâãäå]', 'a', new)
    new = re.sub(r'[èéêë]', 'e', new)
    new = re.sub(r'[ìíîï]', 'i', new)
    new = re.sub(r'[òóôõö]', 'o', new)
    new = re.sub(r'[ùúûü]', 'u', new)
    return new


import unicodedata
from random import choice

import perfplot
import regex
import text_unidecode

def remove_accent_chars_regex(x: str):
    return regex.sub(r'\p{Mn}', '', unicodedata.normalize('NFKD', x))

def remove_accent_chars_join(x: str):
    # answer by MiniQuark
    # https://stackoverflow.com/a/517974/7966259
    return u"".join([c for c in unicodedata.normalize('NFKD', x) if not unicodedata.combining(c)])

    setup=lambda n: ''.join([choice('Málaga François Phút H?n ??') for i in range(n)]),
    labels=['regex', 'join', 'unidecode'],
    n_range=[2 ** k for k in range(22)],
    equality_check=None, relative_to=0, xlabel="str len"

Some languages have combining diacritics as language letters and accent diacritics to specify accent.

I think it is more safe to specify explicitly what diactrics you want to strip:

    accents = set(map(unicodedata.lookup, accents))
    chars = [c for c in unicodedata.normalize('NFD', string) if c not in accents]
    return unicodedata.normalize('NFC', ''.join(chars))

If you are hoping to get functionality similar to Elasticsearch’s asciifolding filter, you might want to consider fold-to-ascii, which is [itself]…

A Python port of the Apache Lucene ASCII Folding Filter that converts alphabetic, numeric, and symbolic Unicode characters which are not in the first 127 ASCII characters (the “Basic Latin” Unicode block) into ASCII equivalents, if they exist.

Here’s an example from the page mentioned above:

from fold_to_ascii import fold
s = u'Astroturf® paté'
> u'Astroturf pate'
fold(s, u'?')
> u'Astroturf? pate'

EDIT: The fold_to_ascii module seems to work well for normalizing Latin-based alphabets; however unmappable characters are removed, which means that this module will reduce Chinese text, for example, to empty strings. If you want to preserve Chinese, Japanese, and other Unicode alphabets, consider using @mo-han’s remove_accent_chars_regex implementation, above.

Here is a short function which strips the diacritics, but keeps the non-latin characters. Most cases (e.g., "à" -> "a") are handled by unicodedata (standard library), but several (e.g., "æ" -> "ae") rely on the given parallel strings.


from unicodedata import combining, normalize

LATIN = "ä  æ  ?  ? ð ƒ ? ? ? ø ? ö  œ  ß  ? ü "
ASCII = "ae ae ae d d f h i l o o oe oe ss t ue"

def remove_diacritics(s, outliers=str.maketrans(dict(zip(LATIN.split(), ASCII.split())))):
    return "".join(c for c in normalize("NFD", s.lower().translate(outliers)) if not combining(c))

NB. The default argument outliers is evaluated once and not meant to be provided by the caller.

Intended usage

As a key to sort a list of strings in a more “natural” order:

sorted(['cote', 'coteau', "crottez", 'crotté', 'côte', 'côté'], key=remove_diacritics)


['cote', 'côte', 'côté', 'coteau', 'crotté', 'crottez']

If your strings mix texts and numbers, you may be interested in composing remove_diacritics() with the function string_to_pairs() I give elsewhere.


To make sure the behavior meets your needs, take a look at the pangrams below:

examples = [
    ("hello, world", "hello, world"),
    ("42", "42"),
    ("?????", "?????"),
        "Dès Noël, où un zéphyr haï me vêt de glaçons würmiens, je dîne d’exquis rôtis de bœuf au kir, à l’aÿ d’âge mûr, &cætera.",
        "des noel, ou un zephyr hai me vet de glacons wuermiens, je dine d’exquis rotis de boeuf au kir, a l’ay d’age mur, &caetera.",
        "Falsches Üben von Xylophonmusik quält jeden größeren Zwerg.",
        "falsches ueben von xylophonmusik quaelt jeden groesseren zwerg.",
        "??????? ????????? ??????? ???? ???? ?? ?? ?????? ????.",
        "??????? ????????? ??????? ???? ???? ?? ?? ?????? ????.",
        "Ljubazni fenjerdžija ?a?avog lica ho?e da mi pokaže štos.",
        "ljubazni fenjerdzija cadavog lica hoce da mi pokaze stos.",
        "Quizdeltagerne spiste jordbær med fløde, mens cirkusklovnen Walther spillede på xylofon.",
        "quizdeltagerne spiste jordbaer med flode, mens cirkusklovnen walther spillede pa xylofon.",
        "Kæmi ný öxi hér ykist þjófum nú bæði víl og ádrepa.",
        "kaemi ny oexi her ykist þjofum nu baedi vil og adrepa.",
        "Gl?žš???a r???ši dz?rum? ?iepj Baha koncertfl??e?u v?kus.",
        "glazskuna rukisi dzeruma ciepj baha koncertfligelu vakus.",

for (given, expected) in examples:
    assert remove_diacritics(given) == expected

Case-preserving variant

LATIN = "ä  æ  ?  ? ð ƒ ? ? ? ø ? ö  œ  ß  ? ü  Ä  Æ  ?  ? Ð ? ? I ? Ø ? Ö  Œ  SS ? Ü "
ASCII = "ae ae ae d d f h i l o o oe oe ss t ue AE AE AE D D F H I L O O OE OE SS T UE"

def remove_diacritics(s, outliers=str.maketrans(dict(zip(LATIN.split(), ASCII.split())))):
    return "".join(c for c in normalize("NFD", s.translate(outliers)) if not combining(c))