[Solved] How to return an array literal in C#
I’m trying the following code. The line with the error is pointed out.
int[] myfunction()
{
{
//regular code
}
catch (Exception ex)
{
return {0,0,0}; //gives error
}
}
How can I return an array literal like string literals?
Solution #1:
Return an array of int like this:
return new int [] { 0, 0, 0 };
You can also implicitly type the array – the compiler will infer it should be int[] because it contains only int values:
return new [] { 0, 0, 0 };
Solution #2:
Blorgbeard is correct, but you also might think about using the new for .NET 4.0 Tuple class. I found it’s easier to work with when you have a set number of items to return. As in if you always need to return 3 items in your array, a 3-int tuple makes it clear what it is.
return new Tuple<int,int,int>(0,0,0);
or simply
return Tuple.Create(0,0,0);
Solution #3:
if the array has a fixed size and you wante to return a new one filled with zeros
return new int[3];
The answers/resolutions are collected from stackoverflow, are licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 .