Rounding to two decimal places in Python 2.7?

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Using Python 2.7 how do I round my numbers to two decimal places rather than the 10 or so it gives?

print "financial return of outcome 1 =","$"+str(out1)

Use the built-in function round():

>>> round(1.2345,2)
1.23
>>> round(1.5145,2)
1.51
>>> round(1.679,2)
1.68

Or built-in function format():

>>> format(1.2345, '.2f')
'1.23'
>>> format(1.679, '.2f')
'1.68'

Or new style string formatting:

>>> "{:.2f}".format(1.2345)
'1.23
>>> "{:.2f}".format(1.679)
'1.68'

Or old style string formatting:

>>> "%.2f" % (1.679)
'1.68'

help on round:

>>> print round.__doc__
round(number[, ndigits]) -> floating point number

Round a number to a given precision in decimal digits (default 0 digits).
This always returns a floating point number.  Precision may be negative.

Since you’re talking about financial figures, you DO NOT WANT to use floating-point arithmetic. You’re better off using Decimal.

>>> from decimal import Decimal
>>> Decimal("33.505")
Decimal('33.505')

Text output formatting with new-style format() (defaults to half-even rounding):

>>> print("financial return of outcome 1 = {:.2f}".format(Decimal("33.505")))
financial return of outcome 1 = 33.50
>>> print("financial return of outcome 1 = {:.2f}".format(Decimal("33.515")))
financial return of outcome 1 = 33.52

See the differences in rounding due to floating-point imprecision:

>>> round(33.505, 2)
33.51
>>> round(Decimal("33.505"), 2)  # This converts back to float (wrong)
33.51
>>> Decimal(33.505)  # Don't init Decimal from floating-point
Decimal('33.50500000000000255795384873636066913604736328125')

Proper way to round financial values:

>>> Decimal("33.505").quantize(Decimal("0.01"))  # Half-even rounding by default
Decimal('33.50')

It is also common to have other types of rounding in different transactions:

>>> import decimal
>>> Decimal("33.505").quantize(Decimal("0.01"), decimal.ROUND_HALF_DOWN)
Decimal('33.50')
>>> Decimal("33.505").quantize(Decimal("0.01"), decimal.ROUND_HALF_UP)
Decimal('33.51')

Remember that if you’re simulating return outcome, you possibly will have to round at each interest period, since you can’t pay/receive cent fractions, nor receive interest over cent fractions. For simulations it’s pretty common to just use floating-point due to inherent uncertainties, but if doing so, always remember that the error is there. As such, even fixed-interest investments might differ a bit in returns because of this.

You can use str.format(), too:

>>> print "financial return of outcome 1 = {:.2f}".format(1.23456)
financial return of outcome 1 = 1.23

When working with pennies/integers. You will run into a problem with 115 (as in $1.15) and other numbers.

I had a function that would convert an Integer to a Float.

...
return float(115 * 0.01)

That worked most of the time but sometimes it would return something like 1.1500000000000001.

So I changed my function to return like this…

...
return float(format(115 * 0.01, '.2f'))

and that will return 1.15. Not '1.15' or 1.1500000000000001 (returns a float, not a string)

I’m mostly posting this so I can remember what I did in this scenario since this is the first result in google.

The best, I think, is to use the format() function:

>>> print("financial return of outcome 1 = $ " + format(str(out1), '.2f'))
// Should print: financial return of outcome 1 = $ 752.60

But I have to say: don’t use round or format when working with financial values.

When we use the round() function, it will not give correct values.

you can check it using,
round (2.735) and round(2.725)

please use

import math
num = input('Enter a number')
print(math.ceil(num*100)/100)

print "financial return of outcome 1 = $%.2f" % (out1)

A rather simple workaround is to convert the float into string first, the select the substring of the first four numbers, finally convert the substring back to float.
For example:

>>> out1 = 1.2345
>>> out1 = float(str(out1)[0:4])
>>> out1

May not be super efficient but simple and works 🙂

Rounding up to the next 0.05, I would do this way:

def roundup(x):
    return round(int(math.ceil(x / 0.05)) * 0.05,2)


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