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I am trying to read and write on the same CSV file:
file1 = open(file.csv, 'rb') file2 = open(file.csv, 'wb') reader = csv.reader(file1) writer = csv.writer(file2) for row in reader: if row == 'Test': writer.writerow( row, row, 'Somevalue')
My csv files are:
So basically if my
row value is
Test I want to replace it with
Some new value.
The above code gives me empty CSV files.
You should use different output file name. Even if you want the name to be the same, you should use some temporary name and finally rename file.
When you open file in ‘w’ (or ‘wb’) mode this file is “cleared” — whole file content disappears. Python documentation for
… ‘w’ for only writing (an existing file with the same name will be erased), …
So your file is erased before csv functions start parsing it.
You can’t open a file in both read and write modes at once.
Your code could be modified as follows:-
# Do the reading file1 = open(file.csv, 'rb') reader = csv.reader(file1) new_rows_list =  for row in reader: if row == 'Test': new_row = [row, row, 'Somevalue'] new_rows_list.append(new_row) file1.close() # <---IMPORTANT # Do the writing file2 = open(file.csv, 'wb') writer = csv.writer(file2) writer.writerows(new_rows_list) file2.close()
As Jason points out, if your CSV is too big for your memory, then you’ll need to write to a different filename and then rename it. This will likely be a bit slower.
If your csv file is not big enough(to explode the memory), read it all into memory and close the file before open it in write mode.
Or you should consider writing to a new file rather than the same one.
It is not possible to open the same file in two different modes in python.You have to release one of the file pointers with file_name.close() before opening the file in another mode!