Python Remove last 3 characters of a string

Each Answer to this Q is separated by one/two green lines.

I’m trying to remove the last 3 characters from a string in python, I don’t know what these characters are so I can’t use rstrip, I also need to remove any white space and convert to upper-case

an example would be:

foo = "Bs12 3ab"
foo.replace(" ", "").rstrip(foo[-3:]).upper()

This works and gives me BS12 which is what I want, however if the last 4th & 3rd characters are the same I loose both eg if foo = "BS11 1AA" I just get 'BS'

examples of foo could be:

BS1 1AB
bs11ab
BS111ab

The string could be 6 or 7 characters and I need to drop the last 3 (assuming no white space)

Any tips?

Removing any and all whitespace:

foo = ''.join(foo.split())

Removing last three characters:

foo = foo[:-3]

Converting to capital letters:

foo = foo.upper()

All of that code in one line:

foo = ''.join(foo.split())[:-3].upper()

It doesn’t work as you expect because strip is character based. You need to do this instead:

foo = foo.replace(' ', '')[:-3].upper()

>>> foo = "Bs12 3ab"
>>> foo[:-3]
'Bs12 '
>>> foo[:-3].strip()
'Bs12'
>>> foo[:-3].strip().replace(" ","")
'Bs12'
>>> foo[:-3].strip().replace(" ","").upper()
'BS12'

You might have misunderstood rstrip slightly, it strips not a string but any character in the string you specify.

Like this:

>>> text = "xxxxcbaabc"
>>> text.rstrip("abc")
'xxxx'

So instead, just use

text = text[:-3] 

(after replacing whitespace with nothing)

>>> foo = 'BS1 1AB'
>>> foo.replace(" ", "").rstrip()[:-3].upper()
'BS1'

I try to avoid regular expressions, but this appears to work:

string = re.sub("\s","",(string.lower()))[:-3]

  1. split
  2. slice
  3. concentrate

This is a good workout for beginners and it’s easy to achieve.

Another advanced method is a function like this:

def trim(s):
    return trim(s[slice])

And for this question, you just want to remove the last characters, so you can write like this:

def trim(s):
    return s[ : -3] 

I think you are over to care about what those three characters are, so you lost. You just want to remove last three, nevertheless who they are!

If you want to remove some specific characters, you can add some if judgements:

def trim(s):
    if [conditions]:   ### for some cases, I recommend using isinstance().
        return trim(s[slice])

What’s wrong with this?

foo.replace(" ", "")[:-3].upper()

Aren’t you performing the operations in the wrong order? You requirement seems to be foo[:-3].replace(" ", "").upper()

It some what depends on your definition of whitespace. I would generally call whitespace to be spaces, tabs, line breaks and carriage returns. If this is your definition you want to use a regex with \s to replace all whitespace charactors:

import re

def myCleaner(foo):
    print 'dirty: ', foo
    foo = re.sub(r'\s', '', foo)
    foo = foo[:-3]
    foo = foo.upper()
    print 'clean:', foo
    print

myCleaner("BS1 1AB")
myCleaner("bs11ab")
myCleaner("BS111ab")


The answers/resolutions are collected from stackoverflow, are licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 .

Leave a Reply

Your email address will not be published.