[Solved] W/System: Ignoring header X-Firebase-Locale because its value was null

Im very new to android studio. I’m trying to make a signup page with email and password authentication with Firebase. Howerver, whenever I try to click the sign up button it gives:

W/System: Ignoring header X-Firebase-Locale because its value was null

Can anyone tell me why?

Here is the file

package com.example.traintrack;

import android.content.Intent;
import android.os.Bundle;
import android.text.TextUtils;
import android.util.Log;
import android.view.View;
import android.widget.AdapterView;
import android.widget.ArrayAdapter;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Spinner;
import android.widget.TextView;
import android.widget.Toast;

import androidx.annotation.NonNull;


import java.util.regex.Pattern;

public class SignupActivity extends AppCompatActivity implements AdapterView.OnItemSelectedListener {
    FirebaseAuth fAuth;
    Button signupBtn;       // Signup Button
    private String userType;
    private TextInputLayout textInputFullName;
    private TextInputLayout textInputEmail;
    private TextInputLayout textInputPassword;
    private boolean submitted = false, validUser = false;
    Spinner spinner;
    public static final Pattern VALID_EMAIL_ADDRESS_REGEX =
            Pattern.compile("^[A-Z0-9._%+-][email protected][A-Z0-9.-]+.[A-Z]{2,6}$", Pattern.CASE_INSENSITIVE);

    private String email;
    private String password;

    //Validating the signup page
    private boolean validateName(){
        String name = textInputFullName.getEditText().getText().toString().trim();

        if (name.isEmpty()){
            textInputFullName.setError("Field can't be empty");
        } else{
            return true;

        return false;
    private boolean validateEmail(){

        String email = textInputEmail.getEditText().getText().toString().trim();

        if (email.isEmpty()){
            textInputEmail.setError("Field can't be empty");
        } else if (!VALID_EMAIL_ADDRESS_REGEX.matcher(email).find()){
            textInputEmail.setError("Please enter a valid email");
        } else {
            return true;
        return false;

    private boolean validatePassword(){
        String password = textInputPassword.getEditText().getText().toString().trim();
        if (password.isEmpty()){
            textInputPassword.setError("Field can't be empty");
        } else if (password.length() < 8){
            textInputPassword.setError("Password must have at least 8 characters");
        } else {
            return true;
        return false;

    //public void confirm(View button){


    protected void onCreate(Bundle savedInstanceState) {

        spinner = findViewById(;
        ArrayAdapter<CharSequence> adapter = ArrayAdapter.createFromResource(this, R.array.user_types, android.R.layout.simple_spinner_item);

        textInputFullName = findViewById(;
        textInputEmail =  findViewById(;
        textInputPassword =  findViewById(;
        signupBtn = findViewById(;

        //Firebase, Sign up by clicking the button
        fAuth = FirebaseAuth.getInstance();

        if (fAuth.getCurrentUser() != null)  // when the current user object is already present
             startActivity(new Intent(getApplicationContext(), MainActivity.class));  //back to main page

        //register the user in firebase
        signupBtn.setOnClickListener(new View.OnClickListener() {
            public void onClick(View v) {
                password = textInputPassword.getEditText().getText().toString().trim();
                email = textInputEmail.getEditText().getText().toString().trim();

                // I have moved the validation here since this is the button for click
                submitted = true;
                if (!validateName() || !validateEmail() || !validatePassword() || !validUser){
                    Toast.makeText(SignupActivity.this, "Cannot create account", Toast.LENGTH_SHORT).show();

                fAuth.createUserWithEmailAndPassword(email,password).addOnCompleteListener(new OnCompleteListener<AuthResult>() {
                    public void onComplete(@NonNull Task<AuthResult> task) {
                        if (task.isSuccessful()) //successfully created the user
                            Toast.makeText(SignupActivity.this, "Account created!", Toast.LENGTH_SHORT).show();
                            startActivity(new Intent (getApplicationContext(), MainActivity.class));
                            } else {

                            Toast.makeText(SignupActivity.this, "Error !", Toast.LENGTH_SHORT).show();


    }//OnCreated Closing

    public void onItemSelected(AdapterView<?> parent, View view, int position, long id) {
        String type = parent.getItemAtPosition(position).toString();
        if (type.equals(getResources().getStringArray(R.array.user_types)[0]) && submitted){
            TextView errorText = (TextView)spinner.getSelectedView();
            errorText.setText("Please select a user type");
        } else {
            validUser = true;
            userType = type;

    public void onNothingSelected(AdapterView<?> parent) {


}  //Ending

Solution #1:

Make sure the emulator is connected to the internet. Sometimes the wifi is on but doesnt connect to the internet. This is how i fixed it anyway.

Respondent: Fergal O Connor

Solution #2:

Have you enabled the Email/Password Sign-in method on your Firebase console?

Firebase Console

Respondent: Anthony Mark

Solution #3:

I have this issue only when I use the emulator on Android Studio. I searched and tested a bit and discovered that this problem doesn’t appear when I use my own phone to launch my app. Like someone else stated before me it might be because of the wifi connection on the emulator.

(I’m quite new to Android Studio, I’m just sharing the way I solved it, hope it helps)

Use this to use your app on your own device:

Respondent: suaibeu

Solution #4:

Add this line to manifest.xml inside application tag:


Solution #5:


  1. Check if your emulator has the permission to access internet and also is connected to.
  2. Email/Password Sign-in method in your firebase console is enabled to gain access.

STEP 1: Create sha1 key + debug key information + Adding firebase.
You probably have your sha1 key only with the normal information from the release key, i guess?

STEP 2: Activate Android Device Verification from and insert your sha keys that are automatically generated by firebase + their matching preferences (like package name…)


Your code looks good to me! Everything is set up right. I think you forgot some trivial settings or the right sha key.
Hope that will help. Cheers buddies! 🙂

Respondent: DEX7RA

Solution #6:

Maybe it is an absurd solution but it worked for me when I wrote a password with more than 6 characters, and more than one I will need this advice;)

Solution #7:

in my case, i just uninstalled my application, and cold booted current emulator device at Android Studio > Configure(outside or at “tools” inside android studio) > AVD Manager > your device, drop down.

then it was working fine. 🙂

Respondent: dhaRani

Solution #8:

I got that error with an app that I made, and I think the error is the length of the password, because if it is less than six digits, the firebase authentication service will be a submit error, try changing the length!

I come to this conclusion because I print the value of it.exception from the addOnCompleteListener and that told me “Password must be at least 6 characters”

Respondent: Nicolas Baez Mora

Solution #9:

I had same error as you. In my case, in the while ,I changed firebase project.
I did clean in android studio and it worked. The google-services.json file generate auto-generated string in android studio. It had to cleaned.

Respondent: Jacob Choi

Solution #10:

Because you are trying to signup an account that there is in your firebase auth list. Go to firebase console -> authentication -> users then delete the user. Try to signup with that again (just once, if you repeat signup with that user you get this error again).

Respondent: FariborZ

Solution #11:

I solved my problem by creating a sha1 key with debug key info and adding firebase.

Then I activated “Android Device Verification” from and entered the sha keys that firebase automatically added and added the necessary definitions (package names, etc.).

Respondent: JonathanLNB

Solution #12:

I was having Same error but using firebase Auth for Email and Password once you delete everything concerning email and password on Firebase console.this error seems to creep in i created a dummy user using add User button and error never went away but i was able to add data to firebase This user Button

Respondent: Felex Kuria

Solution #13:

I had an account with the same email address so I deleted it from “Authentication Users” and from “Database Data” and the problem was fixed!

Respondent: Hamee

Solution #14:

What solved my problem was that firebase upgraded its latest flutter SDK release to null safety and so also all firebase products like firebase messaging and so on.
So upgrading all my dependencies specially firebase_auth and flutter latest stable SDK release did it for me.

Respondent: Shalabyer

Solution #15:

constructor one screen to another screen data send so please arrangement is same with one screen constructor to another screen constructor function is always same*

Another possibility

email and password by mistake add little extra space so please add this type user email and password

Respondent: mewadaarvind

Solution #16:

You are probably missing the instantiation of a variable in your main function of your activity. Android studio is very finicky about details. If you declared it as a variable, you need to instantiate it somewhere in your code.

Respondent: croesus

Solution #17:

It’s not getting current user uid from firebase. So, these errors are produced.
You need to check these first:

final User user = FirebaseAuth.instance.currentUser;
final uid = user.uid;
Respondent: jaimin rana

Solution #18:

You can Use Shared Preferences where you’ll use

Respondent: Sirius92

Solution #19:

you can write “it.exception?.printStackTrace()” and you can know what is problem.
for example ,I wrote it and i found the problem, and I knew I hadn’t written enough character-

W/System.err: The given password is invalid. [ Password should be at least 6 characters ]

Respondent: Murad ?ziz

Solution #20:

just add

await Firebase.initializeApp();
Respondent: Ash’s Project

Solution #21:

Please trust me on this one, I just resolved this a couple of minutes back and am still celebrating this to be solved. What I did was that in the Android Mainifest file, make sure that the java class that connects to the Firebase is declared below the line where the main activity class is declared. I kid you not this actually worked for me.

Respondent: Faizan

Solution #22:

Faced this issue in April, 2021.

The solution — Firebase only accepts the password when it is greater than or equal to 6 characters in length.

Make sure your password is more than or equal to 6 characters in length and your app should start working!

Respondent: Tanmay Sarin

The answers/resolutions are collected from stackoverflow, are licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 .

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