Question

[Solved] How to join on multiple columns in Pyspark?

I am using Spark 1.3 and would like to join on multiple columns using python interface (SparkSQL)

The following works:

I first register them as temp tables.

numeric.registerTempTable("numeric")
Ref.registerTempTable("Ref")

test  = numeric.join(Ref, numeric.ID == Ref.ID, joinType='inner')

I would now like to join them based on multiple columns.

I get SyntaxError: invalid syntax with this:

test  = numeric.join(Ref,
   numeric.ID == Ref.ID AND numeric.TYPE == Ref.TYPE AND
   numeric.STATUS == Ref.STATUS ,  joinType='inner')

Solution #1:

You should use & / | operators and be careful about operator precedence (== has lower precedence than bitwise AND and OR):

df1 = sqlContext.createDataFrame(
    [(1, "a", 2.0), (2, "b", 3.0), (3, "c", 3.0)],
    ("x1", "x2", "x3"))

df2 = sqlContext.createDataFrame(
    [(1, "f", -1.0), (2, "b", 0.0)], ("x1", "x2", "x3"))

df = df1.join(df2, (df1.x1 == df2.x1) & (df1.x2 == df2.x2))
df.show()

## +---+---+---+---+---+---+
## | x1| x2| x3| x1| x2| x3|
## +---+---+---+---+---+---+
## |  2|  b|3.0|  2|  b|0.0|
## +---+---+---+---+---+---+
Respondent: zero323

Solution #2:

An alternative approach would be:

df1 = sqlContext.createDataFrame(
    [(1, "a", 2.0), (2, "b", 3.0), (3, "c", 3.0)],
    ("x1", "x2", "x3"))

df2 = sqlContext.createDataFrame(
    [(1, "f", -1.0), (2, "b", 0.0)], ("x1", "x2", "x4"))

df = df1.join(df2, ['x1','x2'])
df.show()

which outputs:

+---+---+---+---+
| x1| x2| x3| x4|
+---+---+---+---+
|  2|  b|3.0|0.0|
+---+---+---+---+

With the main advantage being that the columns on which the tables are joined are not duplicated in the output, reducing the risk of encountering errors such as org.apache.spark.sql.AnalysisException: Reference 'x1' is ambiguous, could be: x1#50L, x1#57L.


Whenever the columns in the two tables have different names, (let’s say in the example above, df2 has the columns y1, y2 and y4), you could use the following syntax:

df = df1.join(df2.withColumnRenamed('y1','x1').withColumnRenamed('y2','x2'), ['x1','x2'])
Respondent: Florian

Solution #3:

test = numeric.join(Ref, 
   on=[
     numeric.ID == Ref.ID, 
     numeric.TYPE == Ref.TYPE,
     numeric.STATUS == Ref.STATUS 
   ], how='inner')
Respondent: Ander Herrrera

The answers/resolutions are collected from stackoverflow, are licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 .

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