[Solved] How do you fix the “element not interactable” exception?

I know this has been asked lots of times before but how do you get around the “element not interactable” exception?

I’m new to Selenium so excuse me if I get something wrong.

Here is my code:

button = driver.find_element_by_class_name(u"infoDismiss")

Here is the HTML:

<button class="dismiss infoDismiss">
    <string for="inplay_button_dismiss">Dismiss</string>

And here is the error message:

selenium.common.exceptions.ElementNotInteractableException: Message: 

After is says message there is literally nothing.

I have spent lots of time searching the web, not finding anything that solves my issue. I would really appreciate an answer.

Thanks in advance.

Edit: Changed “w” to driver so it is easier to read

Update: I have just realized that I’ve found the HTML of the wrong button! The real button HTML is below:

<button class="dismiss">
    <string for="exit">Dismiss</string>

Also, I’ve used the answers and comments and edited my code to look like this:

button = driver.find_element_by_css_selector("button.dismiss")

And now I get a new error:

selenium.common.exceptions.WebDriverException: Message: Tried to run command without establishing a connection

The error happens in line 1: button = driver.find_element_by_css_selector("button.dismiss")

Note: I really appreciate the help that has been given, thanks

Solution #1:

A possibility is that the element is currently unclickable because it is not visible. Reasons for this may be that another element is covering it up or it is not in view, i.e. it is outside the currently view-able area.

Try this

from selenium.webdriver.common.action_chains import ActionChains

button = driver.find_element_by_class_name(u"infoDismiss")
Respondent: Rolodophone

Solution #2:

The error “Message: element not interactable” mostly occurs when your element is not clickable or it is not visible yet, and you should click or choose one other element before it. Then your element will get displayed and you can modify it.

You can check if your element is visible or not by calling is_displayed() method like this:

print("Element is visible? " + str(element_name.is_displayed()))
Respondent: EyuelDK

Solution #3:

I just ran into a similar issue and was able to fix it by waiting until the button was “clickable”.

from selenium import webdriver
from import By
from import WebDriverWait
from import expected_conditions as EC

chrome_options = webdriver.ChromeOptions()
chrome_options.add_experimental_option('useAutomationExtension', False)
browser = webdriver.Chrome('./chromedriver', options=chrome_options)


button = WebDriverWait(browser, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, 'button.dismiss')))
Respondent: romin parvardeh

Solution #4:

For those discovering this now and the above answers didn’t work, the issue I had was the screen wasn’t big enough. I added this when initializing my ChromeDriver, and it fixed the problem:

Respondent: Adam Polak

Solution #5:

Found a workaround years later after encountering the same problem again – unable to click element even though it SHOULD be clickable. The solution is to catch ElementNotInteractable exception and attempt to execute a script to click the element.

Example in Typescript

async clickElement(element: WebElement) {
    try {
        return await;
    } catch (error) {
        if ( == 'ElementNotInteractableError') {
            return await this.driver.executeScript((element: WebElement) => {
            }, element);
Respondent: robbrit

Solution #6:

I have found that using Thread.sleep(milliseconds) helps almost all the time for me. It takes time for the element to load hence it is not interactable. So i put Thread.sleep() after selecting each value. So far this has helped me avoid the error.

try {Thread.sleep(3000);} catch (InterruptedException e) {e.printStackTrace();}

        Select nationalityDropdown=new Select(driver.findElement("ContentPlaceHolderMain_ddlNationality")));


        try {Thread.sleep(3000);} catch (InterruptedException e) {e.printStackTrace();}     
Respondent: EyuelDK

Solution #7:

I know you may have found the answer , but if there were people looking for it in the future, they may find the solution.OK, straight to the point ,I had a similar problem like this one. When you are usually staring to use this library (selenium webdriver ) one thing that can make you angry is not to know how to use the library ” import time ” that is very import for breaking this type of ” barrier “.

Follow the code snippet below:

Well, my solution was simple and objective. Remembering that you must wait for the element to be clickable (interactable), which is, first use the technique of searching for element by xpath.

buttonNoInteractable = browser.find_element_by_xpath('/html/body/div[2]/div/div/div[2]/div/div/div[2]/div/table[2]/thead/tr/th[2]/input') time.sleep(10)

Or it can be by class name. Use the amount of seconds you need, if you have a slow connection, put it in 30 seconds, or if it is fast, a few seconds less is enough, for example “time.sleep (10)”.

As I said, for me this solution worked very well using python.

send = browser.find_element_by_name('stacks')
Respondent: Sugat Shivsharan

Solution #8:

It will be better to use xpath

from selenium import webdriver
button = driver.find_element_by_xpath('xpath')
Respondent: Daniel Moura

Solution #9:

For the html code:


<button class="dismiss"  onclick="alert('hello')">
    <string for="exit">Dismiss</string>

the below python code worked for me. You can just try it.

from selenium import webdriver
import time

driver = webdriver.Chrome()
button = driver.find_element_by_class_name("dismiss")
Respondent: ???? ????????

Solution #10:

use id of the element except x_path.It will work 100%

Respondent: Ganesh Pai

Solution #11:

It’s worth noting that there is a sleep function built into Selenium.

Respondent: GHULAM NABI

The answers/resolutions are collected from stackoverflow, are licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 .

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