Question

[Solved] get the last sunday and saturday’s date in python

Looking to leverage datetime to get the date of beginning and end of the previous week, sunday to saturday.

So, if it’s 8/12/13 today, I want to define a function that prints:

Last Sunday was 8/4/2013 and last Saturday was 8/10/2013

How do I go about writing this?

EDIT: okay, so there seems to be some question about edge cases. For saturdays, I want the same week, for anything else, I’d like the calendar week immediately preceding today‘s date.

Enquirer: fox

||

Solution #1:

datetime.date.weekday returns 0 for Monday. You need to adjust that.

Try following:

>>> import datetime
>>> today = datetime.date.today()
>>> today
datetime.date(2013, 8, 13)
>>> idx = (today.weekday() + 1) % 7 # MON = 0, SUN = 6 -> SUN = 0 .. SAT = 6
>>> idx
2
>>> sun = today - datetime.timedelta(7+idx)
>>> sat = today - datetime.timedelta(7+idx-6)
>>> 'Last Sunday was {:%m/%d/%Y} and last Saturday was {:%m/%d/%Y}'.format(sun, sat)
'Last Sunday was 08/04/2013 and last Saturday was 08/10/2013'

If you are allowed to use python-dateutil:

>>> import datetime
>>> from dateutil import relativedelta
>>> today = datetime.datetime.now()
>>> start = today - datetime.timedelta((today.weekday() + 1) % 7)
>>> sat = start + relativedelta.relativedelta(weekday=relativedelta.SA(-1))
>>> sun = sat + relativedelta.relativedelta(weekday=relativedelta.SU(-1))
>>> 'Last Sunday was {:%m/%d/%Y} and last Saturday was {:%m/%d/%Y}'.format(sun, sat)
'Last Sunday was 08/04/2013 and last Saturday was 08/10/2013'
Respondent: fox

Solution #2:

I found the best answer from here working fine in my case

try this

from datetime import datetime,timedelta
import time

def last_day(d, day_name):
    days_of_week = ['sunday','monday','tuesday','wednesday',
                        'thursday','friday','saturday']
    target_day = days_of_week.index(day_name.lower())
    delta_day = target_day - d.isoweekday()
    if delta_day >= 0: delta_day -= 7 # go back 7 days
    return d + timedelta(days=delta_day)
Respondent: falsetru

Solution #3:

from datetime import date

def satandsun(input):
    d = input.toordinal()
    last = d - 6
    sunday = last - (last % 7)
    saturday = sunday + 6
    print date.fromordinal(sunday)
    print date.fromordinal(saturday)

Note that this seems to survive all of your cases:

>>> satandsun(date(2013, 8, 10))
2013-08-04
2013-08-10
>>> satandsun(date(2013, 8, 11))
2013-08-04
2013-08-10
>>> satandsun(date(2013, 8, 12))
2013-08-04
2013-08-10
>>> satandsun(date(2013, 8, 13))
2013-08-04
2013-08-10
>>> satandsun(date(2013, 8, 14))
2013-08-04
2013-08-10
>>> satandsun(date(2013, 8, 15))
2013-08-04
2013-08-10
>>> satandsun(date(2013, 8, 16))
2013-08-04
2013-08-10
>>> satandsun(date(2013, 8, 17))
2013-08-11
2013-08-17
Respondent: kartheek

Solution #4:

>>> today = date.today().toordinal()
>>> lastWeek = today-7
>>> sunday = lastWeek - (lastWeek % 7)
>>> saturday = sunday + 6
>>> print "Last Sunday was %s and last Saturday was %s" % (date.fromordinal(sunday), date.fromordinal(saturday))
Last Sunday was 2013-08-04 and last Saturday was 2013-08-10
Respondent: jason

Solution #5:

When I was dealing with this I came with this solution:

from datetime import datetime, timedelta

def prior_week_end():
    return datetime.now() - timedelta(days=((datetime.now().isoweekday() + 1) % 7))

def prior_week_start():
    return prior_week_end() - timedelta(days=6)

So OP could use it as:

'Last Sunday was {:%m/%d/%Y} and last Saturday was {:%m/%d/%Y}'.format(prior_week_start(), prior_week_end())
Respondent: Rob?

Solution #6:

import datetime

d = datetime.datetime.today()    
sat_offset = (d.weekday() - 5) % 7  
saturday = d - datetime.timedelta(days=sat_offset)    
print("Last Saturday was on", saturday)
sun_offset = (d.weekday() - 6) % 7
sunday = d - datetime.timedelta(days=sun_offset)
print("Last Sunday was on", sunday)
Respondent: jozo

The answers/resolutions are collected from stackoverflow, are licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 .

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