Question

[Solved] Do not concatenate text displayed with setText. Use resource string with placeholders

I am a newbie in android development,
I want to setText a number, I am facing this problem and tried all possible ways to solve it.

Please provide me the codes to solve this problem

Codes are as follows:

public class GameActivity extends Activity implements View.OnClickListener{
    int correctAnswer;
    Button buttonObjectChoice1;
    Button buttonObjectChoice2;
    Button buttonObjectChoice3;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    //here we initialize all our varibles
    int partA = 9;
    int partB = 2;
    correctAnswer = partA * partB;
    int wrongAnswer1 = correctAnswer - 1;
    int wrongAnswer2 = correctAnswer + 1;
    TextView textObjectPartA = (TextView)findViewById(R.id.textPartA);
    TextView textObjectPartB = (TextView)findViewById(R.id.textPartB);
    buttonObjectChoice1 = (Button)findViewById(R.id.buttonChoice1);
    buttonObjectChoice2 = (Button)findViewById(R.id.buttonChoice2);
    buttonObjectChoice3 = (Button)findViewById(R.id.buttonChoice3);
    textObjectPartA.setText("" + partA);
    textObjectPartB.setText("" + partB);
    buttonObjectChoice1.setText("" + correctAnswer);
    buttonObjectChoice2.setText("" + wrongAnswer1);
    buttonObjectChoice3.setText("" + wrongAnswer2);
    buttonObjectChoice1.setOnClickListener(this);
    buttonObjectChoice2.setOnClickListener(this);
    buttonObjectChoice3.setOnClickListener(this);

errors in last 8th line to last 4th line.

Error image

Enquirer: Shashwat

||

Solution #1:

the simple solution to your problem is:

textObjectPartA.setText(String.valueOf(partA));
textObjectPartB.setText(String.valueOf(partB));
buttonObjectChoice1.setText(String.valueOf(correctAnswer));
buttonObjectChoice2.setText(String.valueOf(wrongAnswer1));
buttonObjectChoice3.setText(String.valueOf(wrongAnswer2));

what android studio is suggesting you is that if you want to append something in your textview then you have to use placeholders.

example of using placeholders is as follows:

file: strings.xml

...
<string name="part_a">part a value = %1$s.</string>
...

file: activity_main.xml

...
<TextView
    android:id="@+id/R.id.textPartA"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:text="@string/part_a" />
...

filename: GameActivity.java

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    //here we initialize all our varibles
    int partA = 9;
    int partB = 2;
    correctAnswer = partA * partB;
    int wrongAnswer1 = correctAnswer - 1;
    int wrongAnswer2 = correctAnswer + 1;
    TextView textObjectPartA = (TextView)findViewById(R.id.textPartA);
    TextView textObjectPartB = (TextView)findViewById(R.id.textPartB);
    buttonObjectChoice1 = (Button)findViewById(R.id.buttonChoice1);
    buttonObjectChoice2 = (Button)findViewById(R.id.buttonChoice2);
    buttonObjectChoice3 = (Button)findViewById(R.id.buttonChoice3);

    Resources res = getResources();
    String partA_text = String.format(res.getString(R.string.part_a), partA);
    textObjectPartA.setText(partA_text );
...

i hope this clears your doubt. Formatting strings: android developer

Solution #2:

The warning is against concatenating (joining) strings inside the setText() method. As you are assigning integer values the best way to do this is as follows textObjectPartA.setText(String.valueOf(partA));

Respondent: Ivan Wooll

Solution #3:

try making a variable containing your string. then using the variable as your text.
like: String partA_to_text= ""+partA.toString

Respondent: twarped

The answers/resolutions are collected from stackoverflow, are licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 .

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