Question

[Solved] cin.ignore(numeric_limits::max(), ‘n’)

What does cin.ignore(numeric_limits<streamsize>::max(), 'n') mean in C++?

Does it actually ignore the last input from the user?

Enquirer: Zyi

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Solution #1:

This line ignores the rest of the current line, up to 'n' or EOF – whichever comes first:

  • 'n' sets the delimiter, i.e. the character after which cin stops ignoring
  • numeric_limits<streamsize>::max() sets the maximum number of characters to ignore. Since this is the upper limit on the size of a stream, you are effectively telling cin that there is no limit to the number of characters to ignore.

Solution #2:

cin.ignore(numeric_limits < streamsize > ::max(), ‘n’);

Here, the n acts as a delimiter…. that is the point upto which the code has to be ignored(as “n” in this perticular case).
And max() defines that there is no limit for how much can be ignored, the spaces, tabs have to be ignored untill the line ends.

Respondent: Akash sharma

Solution #3:

This code says that the input has to be ignored on 2 basis
-1 if ‘n’ is read
-2 if limit is reached

as limit is max therefore only ‘n’ is the main condition to be considered

Respondent: Pankaj Ramola

The answers/resolutions are collected from stackoverflow, are licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 .

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