[Solved] Angular.js ng-repeat filter by property having one of multiple values (OR of values)

Is it possible to filter an array of objects, such that the value of property can be either of a few values (OR condition) without writing a custom filter

This is similar to this problem – Angular.js ng-repeat :filter by single field

But instead of

<div ng-repeat="product in products | filter: { color: 'red' }">

is it possible to do something like this

<div ng-repeat="product in products | filter: { color: 'red'||'blue' }">

for a sample data as follows-

$scope.products = [
   { id: 1, name: 'test', color: 'red' },
   { id: 2, name: 'bob', color: 'blue' }
   /*... etc... */

I’ve unsuccessfully tried

<div ng-repeat="product in products | filter: { color: ('red'||'blue') }">

Solution #1:

Best way to do this is to use a function:

<div ng-repeat="product in products | filter: myFilter">

$scope.myFilter = function (item) { 
    return item === 'red' || item === 'blue'; 

Alternatively, you can use ngHide or ngShow to dynamically show and hide elements based on a certain criteria.

Respondent: Sherlock

Solution #2:

For me, it worked as given below:

<div ng-repeat="product in products | filter: { color: 'red'||'blue' }">

<div ng-repeat="product in products | filter: { color: 'red'} | filter: { color:'blue' }">
Respondent: Amol Aranke

Solution #3:

I thing ng-if should work:

<div ng-repeat="product in products" ng-if="product.color === 'red' 
|| product.color === 'blue'">
Respondent: jrock10

Solution #4:


<div ng-repeat="product in products | filter: colorFilter">

In Angular:

$scope.colorFilter = function (item) { 
  if (item.color === 'red' || item.color === 'blue') {
  return item;
Respondent: bboyonly

Solution #5:

Here is a way to do it while passing in an extra argument: (thanks to Denis Pshenov)

<div ng-repeat="group in groups">
    <li ng-repeat="friend in friends | filter:weDontLike(">

With the backend:

$scope.weDontLike = function(name) {
    return function(friend) {
        return != name;


And yet another way with an in-template filter only: (thanks to mikel)

<div ng:app>
  <div ng-controller="HelloCntl">
       <li ng-repeat="friend in friends | filter:{name:'!Adam'}">

Respondent: aero

Solution #6:

I found a more generic solution with the most angular-native solution I can think. Basically you can pass your own comparator to the default filterFilter function. Here’s plunker as well.

Respondent: s.alem

Solution #7:

After not able to find a good universal solution I made something of my own. I have not tested it for a very large list.

It takes care of nested keys,arrays or just about anything.

Here is the github and demo

app.filter('xf', function() {
    function keyfind(f, obj) {
        if (obj === undefined)
            return -1;
        else {
            var sf = f.split(".");
            if (sf.length <= 1) {
                return obj[sf[0]];
            } else {
                var newobj = obj[sf[0]];
                sf.splice(0, 1);
                return keyfind(sf.join("."), newobj)

    return function(input, clause, fields) {
        var out = [];
        if (clause && clause.query && clause.query.length > 0) {
            clause.query = String(clause.query).toLowerCase();
            angular.forEach(input, function(cp) {
                for (var i = 0; i < fields.length; i++) {
                    var haystack = String(keyfind(fields[i], cp)).toLowerCase();
                    if (haystack.indexOf(clause.query) > -1) {
        } else {
            angular.forEach(input, function(cp) {
        return out;



<input ng-model="search.query" type="text" placeholder="search by any property">
<div ng-repeat="product in products |  xf:search:['color','name']">
Respondent: Raj Sharma

The answers/resolutions are collected from stackoverflow, are licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 .

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