I need to compare two lists in Python, and I know about using the `set` command to find similar items, but is there a another command I could use that would automatically compare them, instead of having to code for it?

I would like to find the items that aren’t in each one. Say list one is as follows:

``````[1, 2, 3, 4, 5, 6]
``````

and list two is:

``````[1, 2, 3, 4, 6]
``````

I want to find that `5` is missing from the list, hopefully by a command, but I do know how to loop through comparing.

The docs are a good place to start. Here are a couple examples that might help you determine how you want to compare your sets.

To find the intersection (items that are in both sets):

``````>>> a = set([1, 2, 3, 4, 5, 6])
>>> b = set([4, 5, 6, 7, 8, 9])
>>> a & b
set([4, 5, 6])
``````

To find the difference (items that only in one set):

``````>>> a = set([1, 2, 3, 4, 5, 6])
>>> b = set([4, 5, 6, 7, 8, 9])
>>> a - b
set([1, 2, 3])
>>> b - a
set([7, 8, 9])
``````

To find the symmetric difference (items that are in one or the other, but not both):

``````>>> a = set([1, 2, 3, 4, 5, 6])
>>> b = set([4, 5, 6, 7, 8, 9])
>>> a ^ b
set([1, 2, 3, 7, 8, 9])
``````

Hope that helps.

Looks like you need symmetric difference:

``````a = [1,2,3]
b = [3,4,5]

print(set(a)^set(b))

>>> [1,2,4,5]
``````

A simple list comprehension

``````In : a=[1, 2, 3, 4, 5, 6]

In : b=[1, 2, 3, 4, 6]

In : [i for i in a if i not in b]
Out: 
``````