How do I get a Python program to do nothing with if statement?

 if (num2 == num5):
     #No changes are made

You could use a pass statement:

if condition:
    pass

Python 2.x documentation

Python 3.x documentation

However I doubt you want to do this, unless you just need to put something in as a placeholder until you come back and write the actual code for the if statement.

If you have something like this:

if condition:        # condition in your case being `num2 == num5`
    pass
else:
    do_something()

You can in general change it to this:

if not condition:
    do_something()

But in this specific case you could (and should) do this:

if num2 != num5:        # != is the not-equal-to operator
    do_something()

The pass command is what you are looking for. Use pass for any construct that you want to “ignore”. Your example uses a conditional expression but you can do the same for almost anything.

For your specific use case, perhaps you’d want to test the opposite condition and only perform an action if the condition is false:

if num2 != num5:
    make_some_changes()

This will be the same as this:

if num2 == num5:
    pass
else:
    make_some_changes()

That way you won’t even have to use pass and you’ll also be closer to adhering to the “Flatter is better than nested” convention in PEP20.


You can read more about the pass statement in the documentation:

The pass statement does nothing. It can be used when a statement is required syntactically but the program requires no action.

if condition:
    pass
try:
    make_some_changes()
except Exception:
    pass # do nothing
class Foo():
    pass # an empty class definition
def bar():
    pass # an empty function definition

you can use pass inside if statement.

if (num2 == num5):
    for i in []: #do nothing
        do = None
else:
    do = True

or my personal favorite

if (num2 == num5):
    while False: #do nothing
        do = None
else:
    do = True

You can use continue

if condition:
    continue
else:
    #do something