Trying to assert that two dictionaries that have nested contents are equal to each other (order doesn’t matter) with pytest. What’s the pythonic way to do this?

Don’t spend your time writing this logic yourself. Just use the functions provided by the default testing library unittest

from unittest import TestCase
TestCase().assertDictEqual(expected_dict, actual_dict)

pytest’s magic is clever enough. By writing

assert {'a': {'b': 2, 'c': {'d': 4} } } == {'a': {'b': 2, 'c': {'d': 4} } }

you will have a nested test on equality.

I guess a simple assert equality test should be okay:

>>> d1 = {n: chr(n+65) for n in range(10)}
>>> d2 = {n: chr(n+65) for n in range(10)}
>>> d1 == d2
True
>>> l1 = [1, 2, 3]
>>> l2 = [1, 2, 3]
>>> d2[10] = l2
>>> d1[10] = l1
>>> d1 == d2
True
>>> class Example:
    stub_prop = None
>>> e1 = Example()
>>> e2 = Example()
>>> e2.stub_prop = 10
>>> e1.stub_prop = 'a'
>>> d1[11] = e1
>>> d2[11] = e2
>>> d1 == d2
False

General purpose way is to:

import json

# Make sure you sort any lists in the dictionary before dumping to a string

dictA_str = json.dumps(dictA, sort_keys=True)
dictB_str = json.dumps(dictB, sort_keys=True)

assert dictA_str == dictB_str

assert all(v == actual_dict[k] for k,v expected_dict.items()) and len(expected_dict) == len(actual_dict)

your question is not very specific but with what i can understand, you are either trying to check if the length are the same

a = [1,5,3,6,3,2,4]
b = [5,3,2,1,3,5,3]

if (len(a) == len(b)):
    print True
else:
    print false

or checking if the list values are the same

import collections

compare = lambda x, y: collections.Counter(x) == collections.Counter(y)
compare([1,2,3], [1,2,3,3])
print compare #answer would be false
compare([1,2,3], [1,2,3])
print compare #answer would be true

but for dictionaries you could also use

x = dict(a=1, b=2)
y = dict(a=2, b=2)

if(x == y):
    print True
else:
    print False