I want to generate a list of color specifications in the form of (r, g, b) tuples, that span the entire color spectrum with as many entries as I want. So for 5 entries I would want something like:

• (0, 0, 1)
• (0, 1, 0)
• (1, 0, 0)
• (1, 0.5, 1)
• (0, 0, 0.5)

Of course, if there are more entries than combination of 0 and 1 it should turn to use fractions, etc. What would be the best way to do this?

Use the HSV/HSB/HSL color space (three names for more or less the same thing). Generate N tuples equally spread in hue space, then just convert them to RGB.

Sample code:

``````import colorsys
N = 5
HSV_tuples = [(x*1.0/N, 0.5, 0.5) for x in range(N)]
RGB_tuples = map(lambda x: colorsys.hsv_to_rgb(*x), HSV_tuples)
``````

Color palettes are interesting. Did you know that the same brightness of, say, green, is perceived more intensely than, say, red? Have a look at http://poynton.ca/PDFs/ColorFAQ.pdf. If you would like to use preconfigured palettes, have a look at seaborn’s palettes:

``````import seaborn as sns
palette = sns.color_palette(None, 3)
``````

Generates 3 colors from the current palette.

Following the steps of kquinn’s and jhrf 🙂

For Python 3 it can be done the following way:

``````def get_N_HexCol(N=5):
HSV_tuples = [(x * 1.0 / N, 0.5, 0.5) for x in range(N)]
hex_out = []
for rgb in HSV_tuples:
rgb = map(lambda x: int(x * 255), colorsys.hsv_to_rgb(*rgb))
hex_out.append('#%02x%02x%02x' % tuple(rgb))
return hex_out
``````

I created the following function based on kquinn’s answer.

``````import colorsys

def get_N_HexCol(N=5):

HSV_tuples = [(x*1.0/N, 0.5, 0.5) for x in xrange(N)]
hex_out = []
for rgb in HSV_tuples:
rgb = map(lambda x: int(x*255),colorsys.hsv_to_rgb(*rgb))
hex_out.append("".join(map(lambda x: chr(x).encode('hex'),rgb)))
return hex_out
``````

However many number of colors you need and very simple.

``````from matplotlib import cm
n_colors = 10
colours = cm.rainbow(np.linspace(0, 1, n_colors))
``````