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I receive as input a list of strings and need to return a list with these same strings but in randomized order. I must allow for duplicates – same string may appear once or more in the input and must appear the same number of times in the output.
I see several “brute force” ways of doing that (using loops, god forbid), one of which I’m currently using. However, knowing Python there’s probably a cool one-liner do get the job done, right?
>>> import random >>> x = [1, 2, 3, 4, 3, 4] >>> random.shuffle(x) >>> x [4, 4, 3, 1, 2, 3] >>> random.shuffle(x) >>> x [3, 4, 2, 1, 3, 4]
Looks like this is the simplest way, if not the most truly random (this question more fully explains the limitations): http://docs.python.org/library/random.html#random.shuffle
Given a string item, here is a one-liner:
''.join([str(w) for w in random.sample(item, len(item))])
You’ll have to read the strings into an array and then use a shuffling algorithm. I recommend Fisher-Yates shuffle
In python 3.8 you can use the walrus to help cram it into a couple of lines
First you have to create a list from the string and store it into a variable. Then you can use random to shuffle it. Then just join the list back into a string.
random.shuffle(x := list("abcdefghijklmnopqrstuvwxyz")) x = "".join(x)
import random b =  a = int(input(print("How many items you want to shuffle? "))) for i in range(0, a): n = input('Please enter a item: ') b.append(n) random.shuffle(b) print(b)