I want to create a zip file. Add a folder to the zip file and then add a bunch of files to that folder.

So I want to end up with a zip file with a single folder with files in.

I dont know if its bad practice to have folders in zip files or something but google gives me nothing on the subject.

I started out with this:

def addFolderToZip(myZipFile,folder):
folder = folder.encode('ascii') #convert path to ascii for ZipFile Method
for file in glob.glob(folder+"/*"):
if os.path.isfile(file):
print file
myZipFile.write(file, os.path.basename(file), zipfile.ZIP_DEFLATED)
elif os.path.isdir(file):

def createZipFile(filename,files,folders):
curTime=strftime("__%Y_%m_%d", time.localtime())
filename=filename+curTime;
print filename
zipFilename=utils.getFileName("files", filename+".zip")
myZipFile = zipfile.ZipFile( zipFilename, "w" ) # Open the zip file for writing
for file in files:
file = file.encode('ascii') #convert path to ascii for ZipFile Method
if os.path.isfile(file):
(filepath, filename) = os.path.split(file)
myZipFile.write( file, filename, zipfile.ZIP_DEFLATED )

for folder in  folders:
myZipFile.close()
return (1,zipFilename)

(success,filename)=createZipFile(planName,files,folders);


Which gets rid of all folders and puts all files in the target folder (and its subfolders) into a single zip file. I couldnt get it to add an entire folder.

If I feed the path to a folder in myZipFile.write, I get

IOError: [Errno 13] Permission denied: ‘..\packed\bin’

Any help is much welcome.

Related question: How do I zip the contents of a folder using python (version 2.5)?

You can also use shutil

import shutil

zip_name="path\to\zip_file"
directory_name="path\to\directory"

# Create 'path\to\zip_file.zip'
shutil.make_archive(zip_name, 'zip', directory_name)


This will put the whole folder in the zip.

Ok, after i understood what you want, it is as simple as using the second argument of zipfile.write, where you can use whatever you want:

import zipfile
myZipFile = zipfile.ZipFile("zip.zip", "w" )
myZipFile.write("test.py", "dir\\test.py", zipfile.ZIP_DEFLATED )


creates a zipfile where test.py would be extracted to a directory called dir

EDIT:
I once had to create an empty directory in a zip file: it is possible.
after the code above just delete the file test.py from the zipfile, the file is gone, but the empty directory stays.

A zip file has no directory structure, it just has a bunch of pathnames and their contents. These pathnames should be relative to an imaginary root folder (the ZIP file itself). “../” prefixes have no defined meaning in a zip file.

Consider you have a file, a and you want to store it in a “folder” inside a zip file. All you have to do is prefix the filename with a folder name when storing the file in the zipfile:

zipi= zipfile.ZipInfo()
zipi.filename= "folder/a" # this is what you want
zipi.date_time= time.localtime(os.path.getmtime("a"))[:6]
zipi.compress_type= zipfile.ZIP_DEFLATED

zipfile1.writestr(zipi, filedata) # zipfile1 is a zipfile.ZipFile instance


I don’t know of any ZIP implementations allowing the inclusion of an empty folder in a ZIP file. I can think of a workaround (storing a dummy filename in the zip “folder” which should be ignored on extraction), but not portable across implementations.

import zipfile
import os

class ZipUtilities:

def toZip(self, file, filename):
zip_file = zipfile.ZipFile(filename, 'w')
if os.path.isfile(file):
zip_file.write(file)
else:
zip_file.close()

for file in os.listdir(folder):
full_path = os.path.join(folder, file)
if os.path.isfile(full_path):
print 'File added: ' + str(full_path)
zip_file.write(full_path)
elif os.path.isdir(full_path):
print 'Entering folder: ' + str(full_path)

def main():
utilities = ZipUtilities()
filename="TEMP.zip"
directory = 'TEMP'
utilities.toZip(directory, filename)

main()


I’m running:

python tozip.py


This is the log:

[email protected]:~$python tozip.py File added: TEMP/NARF (7ª copia) Entering folder: TEMP/TEMP2 File added: TEMP/TEMP2/NERF (otra copia) File added: TEMP/TEMP2/NERF (copia) File added: TEMP/TEMP2/NARF File added: TEMP/TEMP2/NARF (copia) File added: TEMP/TEMP2/NARF (otra copia) Entering folder: TEMP/TEMP2/TEMP3 File added: TEMP/TEMP2/TEMP3/DOCUMENTO DEL FINAL File added: TEMP/TEMP2/TEMP3/DOCUMENTO DEL FINAL (copia) File added: TEMP/TEMP2/NERF File added: TEMP/NARF (copia) (otra copia) File added: TEMP/NARF (copia) (copia) File added: TEMP/NARF (6ª copia) File added: TEMP/NERF (copia) (otra copia) File added: TEMP/NERF (4ª copia) File added: TEMP/NERF (otra copia) File added: TEMP/NERF (3ª copia) File added: TEMP/NERF (6ª copia) File added: TEMP/NERF (copia) File added: TEMP/NERF (5ª copia) File added: TEMP/NARF (8ª copia) File added: TEMP/NARF (3ª copia) File added: TEMP/NARF (5ª copia) File added: TEMP/NERF (copia) (3ª copia) File added: TEMP/NARF File added: TEMP/NERF (copia) (copia) File added: TEMP/NERF (8ª copia) File added: TEMP/NERF (7ª copia) File added: TEMP/NARF (copia) File added: TEMP/NARF (otra copia) File added: TEMP/NARF (4ª copia) File added: TEMP/NERF File added: TEMP/NARF (copia) (3ª copia)  As you can see, it work, the archive is ok too. This is a recursive function that can zip an entire folder. The only problem is that it doesn’t create a empty folder. Cheers. Below is some code for zipping an entire directory into a zipfile. This seems to work OK creating zip files on both windows and linux. The output files seem to extract properly on windows (built-in Compressed Folders feature, WinZip, and 7-Zip) and linux. However, empty directories in a zip file appear to be a thorny issue. The solution below seems to work but the output of “zipinfo” on linux is concerning. Also the directory permissions are not set correctly for empty directories in the zip archive. This appears to require some more in depth research. I got some info from this velocity reviews thread and this python mailing list thread. Note that this function is designed to put files in the zip archive with either no parent directory or just one parent directory, so it will trim any leading directories in the filesystem paths and not include them inside the zip archive paths. This is generally the case when you want to just take a directory and make it into a zip file that can be extracted in different locations. Keyword arguments: dirPath — string path to the directory to archive. This is the only required argument. It can be absolute or relative, but only one or zero leading directories will be included in the zip archive. zipFilePath — string path to the output zip file. This can be an absolute or relative path. If the zip file already exists, it will be updated. If not, it will be created. If you want to replace it from scratch, delete it prior to calling this function. (default is computed as dirPath + “.zip”) includeDirInZip — boolean indicating whether the top level directory should be included in the archive or omitted. (default True) (Note that StackOverflow seems to be failing to pretty print my python with triple quoted strings, so I just converted my doc strings to the post text here) #!/usr/bin/python import os import zipfile def zipdir(dirPath=None, zipFilePath=None, includeDirInZip=True): if not zipFilePath: zipFilePath = dirPath + ".zip" if not os.path.isdir(dirPath): raise OSError("dirPath argument must point to a directory. " "'%s' does not." % dirPath) parentDir, dirToZip = os.path.split(dirPath) #Little nested function to prepare the proper archive path def trimPath(path): archivePath = path.replace(parentDir, "", 1) if parentDir: archivePath = archivePath.replace(os.path.sep, "", 1) if not includeDirInZip: archivePath = archivePath.replace(dirToZip + os.path.sep, "", 1) return os.path.normcase(archivePath) outFile = zipfile.ZipFile(zipFilePath, "w", compression=zipfile.ZIP_DEFLATED) for (archiveDirPath, dirNames, fileNames) in os.walk(dirPath): for fileName in fileNames: filePath = os.path.join(archiveDirPath, fileName) outFile.write(filePath, trimPath(filePath)) #Make sure we get empty directories as well if not fileNames and not dirNames: zipInfo = zipfile.ZipInfo(trimPath(archiveDirPath) + "https://stackoverflow.com/") #some web sites suggest doing #zipInfo.external_attr = 16 #or #zipInfo.external_attr = 48 #Here to allow for inserting an empty directory. Still TBD/TODO. outFile.writestr(zipInfo, "") outFile.close()  Here’s some sample usages. Note that if your dirPath argument has several leading directories, only the LAST one will be included by default. Pass includeDirInZip=False to omit all leading directories. zipdir("foo") #Just give it a dir and get a .zip file zipdir("foo", "foo2.zip") #Get a .zip file with a specific file name zipdir("foo", "foo3nodir.zip", False) #Omit the top level directory zipdir("../test1/foo", "foo4nopardirs.zip")  Easiest way for me is using zipfile CLI (Command-Line Interface). The zipfile CLI can take either files or folders as arguments, and add them recursively to the archive. So if you have a file hierarcy of: - file1.txt - folder1 - file2.txt - file3.txt  And you want all of it to be archived into ‘result.zip’, you simply write: python -m zipfile -c result.zip file1.txt folder  In case you want to use it within python code and use the zipfile module imported, you can call its main function in the following way: import zipfile zipfile.main(['-c', 'result.zip', 'file1.md', 'folder'])  here is my function i use to zip a folder: import os import os.path import zipfile def zip_dir(dirpath, zippath): fzip = zipfile.ZipFile(zippath, 'w', zipfile.ZIP_DEFLATED) basedir = os.path.dirname(dirpath) + "https://stackoverflow.com/" for root, dirs, files in os.walk(dirpath): if os.path.basename(root)[0] == '.': continue #skip hidden directories dirname = root.replace(basedir, '') for f in files: if f[-1] == '~' or (f[0] == '.' and f != '.htaccess'): #skip backup files and all hidden files except .htaccess continue fzip.write(root + "https://stackoverflow.com/" + f, dirname + "https://stackoverflow.com/" + f) fzip.close()  If you look at a zip file created with Info-ZIP, you’ll see that directories are indeed listed: $ zip foo.zip -r foo
$less foo.zip Archive: foo.zip Length Method Size Cmpr Date Time CRC-32 Name -------- ------ ------- ---- ---------- ----- -------- ---- 0 Stored 0 0% 2013-08-18 14:32 00000000 foo/ 476320 Defl:N 77941 84% 2013-08-18 14:31 55a52268 foo/foo.jpg -------- ------- --- ------- 476320 77941 84% 2 files  Notice that the directory entry has zero length and is not compressed. It seems you can achieve the same thing with Python by writing the directory by name, but forcing it to not use compression. if os.path.isdir(name): zf.write(name, arcname=arcname, compress_type=zipfile.ZIP_STORED) else: zf.write(name, arcname=arcname, compress_type=zipfile.ZIP_DEFLATED)  It might be worth making sure arcname ends in a /. after adding some imports your code runs fine for me, how do you call the script, maybe you could tell us the folder structure of the ‘..\packed\bin’ directory. I called your code with the following arguments: planName="test.zip" files=['z.py',] folders=['c:\\temp'] (success,filename)=createZipFile(planName,files,folders)   Heres the edited code I ran. Its based on the code above, taken from the mailing list. I added the imports and made a main routine. I also cut out the fiddling with the output filename to make the code shorter. #!/usr/bin/env python import os, zipfile, glob, sys def addFolderToZip(myZipFile,folder): folder = folder.encode('ascii') #convert path to ascii for ZipFile Method for file in glob.glob(folder+"/*"): if os.path.isfile(file): print file myZipFile.write(file, os.path.basename(file), zipfile.ZIP_DEFLATED) elif os.path.isdir(file): addFolderToZip(myZipFile,file) def createZipFile(filename,files,folders): myZipFile = zipfile.ZipFile( filename, "w" ) # Open the zip file for writing for file in files: file = file.encode('ascii') #convert path to ascii for ZipFile Method if os.path.isfile(file): (filepath, filename) = os.path.split(file) myZipFile.write( file, filename, zipfile.ZIP_DEFLATED ) for folder in folders: addFolderToZip(myZipFile,folder) myZipFile.close() return (1,filename) if __name__=="__main__": #put everything in sys.argv[1] in out.zip, skip files print createZipFile("out.zip", [], sys.argv[1])  At work, on my Windows box, this code ran fine but didnt create any “folders” in the zipfile. At least I recall it did. Now at home, on my Linux box, the zip file created seems to be bad: $ unzip -l out.zip
Archive:  out.zip
a zipfile, or it constitutes one disk of a multi-part archive.  In the
latter case the central directory and zipfile comment will be found on
the last disk(s) of this archive.
unzip:  cannot find zipfile directory in one of out.zip or
out.zip.zip, and cannot find out.zip.ZIP, period.


I dont know if I accidently broke the code, I think its the same. Crossplatform issues? Either way, its not related to my original question; getting folders in the zip file. Just wanted to post the code I actually ran, not the code I based my code on.

Thank you wery much for this useful function! I found it very useful as I was also searching for help. However, maybe it would be useful to change it a little bit so that

basedir = os.path.dirname(dirpath) + "https://stackoverflow.com/"


would be

basedir = os.path.dirname(dirpath + "https://stackoverflow.com/")


Because found that if I want to zip folder ‘Example’ which is located at ‘C:\folder\path\notWanted\to\zip\Example’,

I got in Windows:

dirpath="C:\folder\path\notWanted\to\zip\Example"
basedir="C:\folder\path\notWanted\to\zip\Example/"
dirname="C:\folder\path\notWanted\to\zip\Example\Example\Subfolder_etc"


But I suppose your code should give

dirpath="C:\folder\path\notWanted\to\zip\Example"
basedir="C:\folder\path\notWanted\to\zip\Example\"
dirname="\Subfolder_etc"


import os
import zipfile

zf = zipfile.ZipFile("file.zip", "w")
for file in os.listdir(os.curdir):
if not file.endswith('.zip') and os.path.isfile(os.curdir+"https://stackoverflow.com/"+file):
print file
zf.write(file)
elif os.path.isdir(os.curdir+"https://stackoverflow.com/"+file):
print f
for f in os.listdir(os.curdir+"https://stackoverflow.com/"+file):
zf.write(file+'\\'+f)
zf.close()


When you wanna create an empty folder, you can do it like this:

    storage = api.Storage.open("empty_folder.zip","w")
res = storage.open_resource("hannu//","w")
storage.close()
`

Folder not showe in winextractor, but when you extract it it is showed.