Iterate through pairs of items in a Python list [duplicate]

Each Answer to this Q is separated by one/two green lines.

Possible Duplicates:
Iterate a list as pair (current, next) in Python
Iterating over every two elements in a list

Is it possible to iterate a list in the following way in Python (treat this code as pseudocode)?

a = [5, 7, 11, 4, 5]
for v, w in a:
    print [v, w]

And it should produce

[5, 7]
[7, 11]
[11, 4]
[4, 5]

You can zip the list with itself sans the first element:

a = [5, 7, 11, 4, 5]

for previous, current in zip(a, a[1:]):
    print(previous, current)

This works even if your list has no elements or only 1 element (in which case zip returns an empty iterable and the code in the for loop never executes). It doesn’t work on generators, only sequences (tuple, list, str, etc).

From the itertools recipes:

from itertools import tee

def pairwise(iterable):
    "s -> (s0,s1), (s1,s2), (s2, s3), ..."
    a, b = tee(iterable)
    next(b, None)
    return zip(a, b)

for v, w in pairwise(a):
    ...

To do that you should do:

a =  [5, 7, 11, 4, 5]
for i in range(len(a)-1):
    print [a[i], a[i+1]]

Nearly verbatim from Iterate over pairs in a list (circular fashion) in Python:

def pairs(seq):
    i = iter(seq)
    prev = next(i)
    for item in i:
        yield prev, item
        prev = item

>>> a = [5, 7, 11, 4, 5]
>>> for n,k in enumerate(a[:-1]):
...     print a[n],a[n+1]
...
5 7
7 11
11 4
4 5


The answers/resolutions are collected from stackoverflow, are licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 .

Leave a Reply

Your email address will not be published.