How to find the last row in a column using openpyxl normal workbook?

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I’m using openpyxl to put data validation to all rows that have “Default” in them. But to do that, I need to know how many rows there are.

I know there is a way to do that if I were using Iterable workbook mode, but I also add a new sheet to the workbook and in the iterable mode that is not possible.

ws.max_row will give you the number of rows in a worksheet.

Since version openpyxl 2.4 you can also access individual rows and columns and use their length to answer the question.

len(ws['A'])

Though it’s worth noting that for data validation for a single column Excel uses 1:1048576.

This works for me well. It gives number of non empty rows in each column, assuming there are no empty rows in between.

from openpyxl import load_workbook as lw
from openpyxl.utils import get_column_letter

wb = lw(your_xlsx_file)
ws = wb[sheet_name]

for col in range(1, ws.max_column + 1):
    col_letter = get_column_letter(col)
    max_col_row = len([cell for cell in ws[col_letter] if cell.value])
    print("Column: {}, Row numbers: {}".format(col_letter, max_col_row)

Find length of row and length of col.

Column:

column=sheet['A']
output tuple-->(A1,A2,A3........An)

len(column)
output length--> 18                    

for row length:

for i in sheet.iter_rows(max_row=0):

    print(len(i))

    break

This will give you length of header row where you put feature name .
If you wan to get all rows length add max_row=len(column) and remove break.


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