How do I get the full path of the current file’s directory?

Each Answer to this Q is separated by one/two green lines.

I want to get the current file’s directory path.
I tried:

>>> os.path.abspath(__file__)

But how can I retrieve the directory’s path?

For example:


The special variable __file__ contains the path to the current file. From that we can get the directory using either Pathlib or the os.path module.

Python 3

For the directory of the script being run:

import pathlib

For the current working directory:

import pathlib

Python 2 and 3

For the directory of the script being run:

import os

If you mean the current working directory:

import os

Note that before and after file is two underscores, not just one.

Also note that if you are running interactively or have loaded code from something other than a file (eg: a database or online resource), __file__ may not be set since there is no notion of “current file”. The above answer assumes the most common scenario of running a python script that is in a file.


  1. pathlib in the python documentation.
  2. os.path – Python 2.7, os.path – Python 3
  3. os.getcwd – Python 2.7, os.getcwd – Python 3
  4. what does the __file__ variable mean/do?

Using Path is the recommended way since Python 3:

from pathlib import Path
print("File      Path:", Path(__file__).absolute())
print("Directory Path:", Path().absolute()) # Directory of current working directory, not __file__  

Documentation: pathlib

Note: If using Jupyter Notebook, __file__ doesn’t return expected value, so Path().absolute() has to be used.

In Python 3.x I do:

from pathlib import Path

path = Path(__file__).parent.absolute()


  • Path(__file__) is the path to the current file.
  • .parent gives you the directory the file is in.
  • .absolute() gives you the full absolute path to it.

Using pathlib is the modern way to work with paths. If you need it as a string later for some reason, just do str(path).

Try this:

import os
dir_path = os.path.dirname(os.path.realpath(__file__))

import os
print os.path.dirname(__file__)

I found the following commands return the full path of the parent directory of a Python 3 script.

Python 3 Script:

#!/usr/bin/env python3
# -*- coding: utf-8 -*-

from pathlib import Path

#Get the absolute path of a Python3.6 and above script.
dir1 = Path().resolve()  #Make the path absolute, resolving any symlinks.
dir2 = Path().absolute() #See @RonKalian answer 
dir3 = Path(__file__).parent.absolute() #See @Arminius answer
dir4 = Path(__file__).parent 



  1. dir1 and dir2 works only when running a script located in the current working directory, but will break in any other case.
  2. Given that Path(__file__).is_absolute() is True, the use of the .absolute() method in dir3 appears redundant.
  3. The shortest command that works is dir4.

Explanation links: .resolve(), .absolute(), Path(file).parent().absolute()

IPython has a magic command %pwd to get the present working directory. It can be used in following way:

from IPython.terminal.embed import InteractiveShellEmbed

ip_shell = InteractiveShellEmbed()

present_working_directory = ip_shell.magic("%pwd")

On IPython Jupyter Notebook %pwd can be used directly as following:

present_working_directory = %pwd


 from pathlib import Path

    #Returns the path of the directory, where your script file is placed
    mypath = Path().absolute()
    print('Absolute path : {}'.format(mypath))

    #if you want to go to any other file inside the subdirectories of the directory path got from above method
    filePath = mypath/'data""fuel_econ.csv'
    print('File path : {}'.format(filePath))

    #To check if file present in that directory or Not
    isfileExist = filePath.exists()
    print('isfileExist : {}'.format(isfileExist))

    #To check if the path is a directory or a File
    isadirectory = filePath.is_dir()
    print('isadirectory : {}'.format(isadirectory))

    #To get the extension of the file
    fileExtension = mypath/'data""fuel_econ.csv'
    print('File extension : {}'.format(filePath.suffix))


Absolute path : D:\Study\Machine Learning\Jupitor Notebook\JupytorNotebookTest2\Udacity_Scripts\Matplotlib and seaborn Part2

File path : D:\Study\Machine Learning\Jupitor Notebook\JupytorNotebookTest2\Udacity_Scripts\Matplotlib and seaborn Part2\data\fuel_econ.csv

isfileExist : True

isadirectory : False

File extension : .csv

I have made a function to use when running python under IIS in CGI in order to get the current folder:

import os 
def getLocalFolder():
    return path[len(path)-1]

The answers/resolutions are collected from stackoverflow, are licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 .

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